-10v^2-28v-16=0

Solution for -10v^2-28v-16=0 equation:

-10v^2-28v-16=0

a = -10; b = -28; c = -16;
Δ = b2-4ac
Δ = -282-4·(-10)·(-16)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-12}{2*-10}=\frac{16}{-20}
=-4/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+12}{2*-10}=\frac{40}{-20}
=-2
$